[JAVA] Remove leading or trailing spaces in a String using regular expressions

import java.util.regex.*;

public class BlankRemover
{

    /* remove leading whitespace */
    public static String ltrim(String source) {
        return source.replaceAll("^\\s+&qu  ot;, "");
    }

    /* remove trailing whitespace */
    public static String rtrim(String source) {
        return source.replaceAll("\\s+$&qu  ot;, "");
    }

    /* replace multiple whitespaces between words with single blank */
    public static String itrim(String source) {
        return source.replaceAll("\\b\\s{2  ,}\\b", " ");
    }

    /* remove all superfluous whitespaces in source string */
    public static String trim(String source) {
        return itrim(ltrim(rtrim(source)  ));
    }

    public static String lrtrim(String source){
        return ltrim(rtrim(source));
    }

    public static void main(String[] args){
        String oldStr =
         ">     <1-2-1-2-1-2-1-2-1-2-1  -----2-1-2-1-2-1-2-1-2-1-  2-1-2>   <";
        String newStr = oldStr.replaceAll("-",   " ");
        System.out.println(newStr);
        System.out.println(ltrim(newStr));
        System.out.println(rtrim(newStr));
        System.out.println(itrim(newStr));
        System.out.println(lrtrim(newStr));
    }

}